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index 2065cfae91d76045cfbaeccf162d7c1df069deda..dba5d48ea80c434114ad3b6441c5390d9b823499 100644 (file)
-#!/usr/bin/env python
-'''
-Copyright (C) 2007 Martin Owens
-
-Thanks to Lineaire Chez of Inkbar ( www.inkbar.lineaire.net )
-
-This program is free software; you can redistribute it and/or modify
-it under the terms of the GNU General Public License as published by
-the Free Software Foundation; either version 2 of the License, or
-(at your option) any later version.
-
-This program is distributed in the hope that it will be useful,
-but WITHOUT ANY WARRANTY; without even the implied warranty of
-MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
-GNU General Public License for more details.
-
-You should have received a copy of the GNU General Public License
-along with this program; if not, write to the Free Software
-Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
-'''
-
-import EAN13
-from EAN13 import mapLeftFaimly, guardBar, centerBar
+#
+# Copyright (C) 2010 Martin Owens
+#
+# This program is free software; you can redistribute it and/or modify
+# it under the terms of the GNU General Public License as published by
+# the Free Software Foundation; either version 2 of the License, or
+# (at your option) any later version.
+#
+# This program is distributed in the hope that it will be useful,
+# but WITHOUT ANY WARRANTY; without even the implied warranty of
+# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
+# GNU General Public License for more details.
+#
+# You should have received a copy of the GNU General Public License
+# along with this program; if not, write to the Free Software
+# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
+#
+"""
+Python barcode renderer for UPCE barcodes. Designed for use with Inkscape.
+"""
+
+from BaseEan import EanBarcode
import sys
-mapFamily = [ '000111','001011','001101','001110','010011','011001','011100','010101','010110','011010' ]
-
-class Object(EAN13.Object):
- def encode(self, number):
- result = ''
-
- l = len(number)
-
- if (l != 6 and l != 7 and l != 11 and l != 12) or not number.isdigit():
- sys.stderr.write("Can not encode '" + number + "' into UPC-E Barcode, Size must be 6 numbers only, and 1 check digit (optional)\nOr a convertable 11 digit UPC-A number with 1 check digit (also optional).\n")
- return
-
- echeck = None
- if l==7 or l==12:
- echeck = number[-1]
- number = number[:-1]
- sys.stderr.write("CHECKSUM FOUND!")
- l -= 1
-
- if l==6:
- number = self.ConvertEtoA(number)
-
- if not echeck:
- echeck = self.getChecksum(number)
- else:
- if not self.verifyChecksum(number + echeck):
- sys.stderr.write("UPC-E Checksum not correct for this barcode, omit last character to generate new checksum.\n")
- return
-
- number = self.ConvertAtoE(number)
- if not number:
- sys.stderr.write("UPC-A code could not be converted into a UPC-E barcode, please follow the UPC guide or enter a 6 digit UPC-E number..\n")
- return
-
- number = number
-
- result = result + guardBar
- # The check digit isn't stored as bars but as a mirroring system. :-(
- family = mapFamily[int(echeck)]
-
- i = 0
- for i in range(0,6):
- result += mapLeftFaimly[int(family[i])-1][int(number[i])]
-
- result = result + centerBar + '2';
-
- self.label = '0 ' + number[:6] + ' ' + echeck
- self.inclabel = self.label
- return result;
-
- def fontSize(self):
- return '10'
-
- def ConvertAtoE(self, number):
- # Converting UPC-A to UPC-E
-
- # All UPC-E Numbers use number system 0
- if number[0] != '0' or len(number)!=11:
- # If not then the code is invalid
- return None
-
- # Most of the conversions deal
- # with the specific code parts
- manufacturer = number[1:6]
- product = number[6:11]
-
- # There are 4 cases to convert:
- if manufacturer[2:] == '000' or manufacturer[2:] == '100' or manufacturer[2:] == '200':
- # Maxium number product code digits can be encoded
- if product[:2]=='00':
- return manufacturer[:2] + product[2:] + manufacturer[2]
- elif manufacturer[3:5] == '00':
- # Now only 2 product code digits can be used
- if product[:3]=='000':
- return manufacturer[:3] + product[3:] + '3'
- elif manufacturer[4] == '0':
- # With even more manufacturer code we have less room for product code
- if product[:4]=='0000':
- return manufacturer[0:4] + product[4] + '4'
- elif product[:4]=='0000' and int(product[4]) > 4:
- # The last recorse is to try and squeeze it in the last 5 numbers
- # so long as the product is 00005-00009 so as not to conflict with
- # the 0-4 used above.
- return manufacturer + product[4]
- else:
- # Invalid UPC-A Numbe
- return None
-
- def ConvertEtoA(self, number):
- # Convert UPC-E to UPC-A
-
- # It's more likly to convert this without fault
- # But we still must be mindful of the 4 conversions
- if len(number)!=6:
- return None
-
- if number[5]=='0' or number[5]=='1' or number[5]=='2':
- return '0' + number[:2] + number[5] + '0000' + number[2:5]
- elif number[5]=='3':
- return '0' + number[:3] + '00000' + number[3:5]
- elif number[5]=='4':
- return '0' + number[:4] + '00000' + number[4]
- else:
- return '0' + number[:5] + '0000' + number[5]
+# This is almost exactly the same as the standard FAMILIES
+# But flipped around and with the first 111000 instead of 000000.
+FAMS = [ '111000', '110100', '110010', '110001', '101100',
+ '100110', '100011', '101010', '101001', '100101' ]
+
+class Object(EanBarcode):
+ """Generate EAN6/UPC-E barcode generator"""
+ name = 'upce'
+ lengths = [ 6, 11 ]
+ checks = [ 7, 12 ]
+
+ def _encode(self, n):
+ """Generate a UPC-E Barcode"""
+ self.label = self.space(['0'], 2, n[:6], 2, n[-1])
+ code = self.encode_interleaved(n[-1], n[:6], FAMS)
+ # 202(guard) + code + 020(center) + 202(guard)
+ return self.enclose(code, center='020')
+
+ def appendChecksum(self, number):
+ """Generate a UPCE Checksum"""
+ if len(number) == 6:
+ number = self.ConvertEtoA(number)
+ result = self.getChecksum(number)
+ return self.ConvertAtoE(number) + result
+
+ def fontSize(self):
+ """We need a font size of 10"""
+ return 10
+
+ def ConvertAtoE(self, number):
+ """Converting UPC-A to UPC-E, may cause errors."""
+ # All UPC-E Numbers use number system 0
+ if number[0] != '0' or len(number)!=11:
+ # If not then the code is invalid
+ return None
+
+ # Most of the conversions deal
+ # with the specific code parts
+ manufacturer = number[1:6]
+ product = number[6:11]
+
+ # There are 4 cases to convert:
+ if manufacturer[2:] == '000' or manufacturer[2:] == '100' or manufacturer[2:] == '200':
+ # Maxium number product code digits can be encoded
+ if product[:2]=='00':
+ return manufacturer[:2] + product[2:] + manufacturer[2]
+ elif manufacturer[3:5] == '00':
+ # Now only 2 product code digits can be used
+ if product[:3]=='000':
+ return manufacturer[:3] + product[3:] + '3'
+ elif manufacturer[4] == '0':
+ # With even more manufacturer code we have less room for product code
+ if product[:4]=='0000':
+ return manufacturer[0:4] + product[4] + '4'
+ elif product[:4]=='0000' and int(product[4]) > 4:
+ # The last recorse is to try and squeeze it in the last 5 numbers
+ # so long as the product is 00005-00009 so as not to conflict with
+ # the 0-4 used above.
+ return manufacturer + product[4]
+ else:
+ # Invalid UPC-A Numbe
+ return None
+
+ def ConvertEtoA(self, number):
+ """Convert UPC-E to UPC-A by padding with zeros"""
+ # It's more likly to convert this without fault
+ # But we still must be mindful of the 4 conversions
+ if len(number) != 6:
+ return None
+
+ if number[5] in ['0', '1', '2']:
+ return '0' + number[:2] + number[5] + '0000' + number[2:5]
+ elif number[5] == '3':
+ return '0' + number[:3] + '00000' + number[3:5]
+ elif number[5] == '4':
+ return '0' + number[:4] + '00000' + number[4]
+ else:
+ return '0' + number[:5] + '0000' + number[5]