From 4ce6fb805803cd9bf82c08c84a2fdc8cd6bae8ef Mon Sep 17 00:00:00 2001 From: Johannes Sixt Date: Tue, 7 Sep 2010 21:33:02 +0200 Subject: [PATCH] fast-export: ensure that a renamed file is printed after all references t9350 sets up a commit where a file is both copied and renamed. The output of fast-export for this commit should look like this: author ... committer ... from :19 C "file2" "file4" R "file2" "file5" The order of the two modification lines is derived from the result that the diff machinery produces. 060df62 (fast-export: Fix output order of D/F changes) inserted a qsort call that modifies the order of the diff result. Unfortunately, qsort need not be stable. Therefore, it is possible that the 'R' line appears before the 'C' line and the resulting fast-import stream is incorrect. Fix it by forcing that the rename entry is printed after all other modification lines with the same file name. Signed-off-by: Johannes Sixt Signed-off-by: Junio C Hamano --- builtin/fast-export.c | 10 +++++++++- 1 file changed, 9 insertions(+), 1 deletion(-) diff --git a/builtin/fast-export.c b/builtin/fast-export.c index 965e90e5e..007bba679 100644 --- a/builtin/fast-export.c +++ b/builtin/fast-export.c @@ -166,7 +166,15 @@ static int depth_first(const void *a_, const void *b_) cmp = memcmp(name_a, name_b, len); if (cmp) return cmp; - return (len_b - len_a); + cmp = len_b - len_a; + if (cmp) + return cmp; + /* + * Move 'R'ename entries last so that all references of the file + * appear in the output before it is renamed (e.g., when a file + * was copied and renamed in the same commit). + */ + return (a->status == 'R') - (b->status == 'R'); } static void show_filemodify(struct diff_queue_struct *q, -- 2.30.2