Code

smart-http: Don't deadlock on server failure
authorShawn O. Pearce <spearce@spearce.org>
Fri, 6 Aug 2010 21:19:44 +0000 (14:19 -0700)
committerJunio C Hamano <gitster@pobox.com>
Fri, 6 Aug 2010 22:30:16 +0000 (15:30 -0700)
If the remote HTTP server fails (e.g. returns 404 or 500) when we
posted the RPC to it, we won't have sent anything to the background
Git process that is supposed to handle the stream.  Because we
didn't send anything, its waiting for input from remote-curl, and
remote-curl cannot read its response payload because doing so would
lead to a deadlock.

Send the background task EOF on its input before we try to read
its response back, that way it will break out of its read loop
and terminate.

Signed-off-by: Shawn O. Pearce <spearce@spearce.org>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
remote-curl.c

index 3edbf5717c94f3123a97939acf265cc8334ca899..5416891c8cc3c3b51250567d2bb16df0019b7b2d 100644 (file)
@@ -505,11 +505,12 @@ static int rpc_service(struct rpc_state *rpc, struct discovery *heads)
                rpc->len = n;
                err |= post_rpc(rpc);
        }
-       strbuf_read(&rpc->result, client.out, 0);
 
        close(client.in);
-       close(client.out);
        client.in = -1;
+       strbuf_read(&rpc->result, client.out, 0);
+
+       close(client.out);
        client.out = -1;
 
        err |= finish_command(&client);