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diff --git a/roundup/date.py b/roundup/date.py
index 69c9935bb3fbd9286104461fec2d672ef25351ec..49151768aedaf563b78e76c689702609803b671d 100644 (file)
--- a/roundup/date.py
+++ b/roundup/date.py
# BASIS, AND THERE IS NO OBLIGATION WHATSOEVER TO PROVIDE MAINTENANCE,
# SUPPORT, UPDATES, ENHANCEMENTS, OR MODIFICATIONS.
#
-# $Id: date.py,v 1.55 2003-11-03 10:23:05 anthonybaxter Exp $
+# $Id: date.py,v 1.59 2003-12-05 03:28:38 richard Exp $
__doc__ = """
Date, time and time interval handling.
# now cope with under- and over-flow
# first do the time
while (second < 0 or second > 59 or minute < 0 or minute > 59 or
- hour < 0 or hour > 59):
+ hour < 0 or hour > 23):
if second < 0: minute -= 1; second += 60
elif second > 59: minute += 1; second -= 60
if minute < 0: hour -= 1; minute += 60
elif minute > 59: hour += 1; minute -= 60
if hour < 0: day -= 1; hour += 24
- elif hour > 59: day += 1; hour -= 24
+ elif hour > 23: day += 1; hour -= 24
# fix up the month so we're within range
while month < 1 or month > 12:
if month > 12: year += 1; month -= 12
# now do the days, now that we know what month we're in
- def get_mdays(year,month):
+ def get_mdays(year, month):
if month == 2 and calendar.isleap(year): return 29
else: return calendar.mdays[month]
-
- while month < 1 or month > 12 or day < 0 or day > get_mdays(year,month):
+
+ while month < 1 or month > 12 or day < 1 or day > get_mdays(year,month):
# now to day under/over
- if day < 0:
+ if day < 1:
# When going backwards, decrement month, then increment days
month -= 1
day += get_mdays(year,month)
return (year, month, day, hour, minute, second, 0, 0, 0)
+ def differenceDate(self, other):
+ "Return the difference between this date and another date"
+
def applyInterval(self, interval):
''' Apply the interval to this date
'''
assert isinstance(other, Date), 'May only subtract Dates or Intervals'
- # TODO this code will fall over laughing if the dates cross
- # leap years, phases of the moon, ....
+ return self.dateDelta(other)
+
+ def dateDelta(self, other):
+ """ Produce an Interval of the difference between this date
+ and another date. Only returns days:hours:minutes:seconds.
+ """
+ # Returning intervals larger than a day is almost
+ # impossible - months, years, weeks, are all so imprecise.
a = calendar.timegm((self.year, self.month, self.day, self.hour,
self.minute, self.second, 0, 0, 0))
b = calendar.timegm((other.year, other.month, other.day,
other.hour, other.minute, other.second, 0, 0, 0))
diff = a - b
- if diff < 0:
+ if diff > 0:
sign = 1
- diff = -diff
else:
sign = -1
+ diff = -diff
S = diff%60
M = (diff/60)%60
- H = (diff/(60*60))%60
- if H>1: S = 0
- d = (diff/(24*60*60))%30
- if d>1: H = S = M = 0
- m = (diff/(30*24*60*60))%12
- if m>1: H = S = M = 0
- y = (diff/(365*24*60*60))
- if y>1: d = H = S = M = 0
- return Interval((y, m, d, H, M, S), sign=sign)
+ H = (diff/(60*60))%24
+ d = diff/(24*60*60)
+ return Interval((0, 0, d, H, M, S), sign=sign)
def __cmp__(self, other):
"""Compare this date to another date."""
return '%4d%02d%02d%02d%02d%02d'%(self.year, self.month,
self.day, self.hour, self.minute, self.second)
+ def timestamp(self):
+ ''' return a UNIX timestamp for this date '''
+ return calendar.timegm((self.year, self.month, self.day, self.hour,
+ self.minute, self.second, 0, 0, 0))
+
class Interval:
'''
Date intervals are specified using the suffixes "y", "m", and "d". The
raise TypeError, "Can't add %r"%other
def __div__(self, other):
- ''' Divide this interval by an int value.
+ """ Divide this interval by an int value.
Can't divide years and months sensibly in the _same_
calculation as days/time, so raise an error in that situation.
- '''
+ """
try:
other = float(other)
except TypeError:
'''
if self.year:
if self.year == 1:
- return _('1 year')
+ s = _('1 year')
else:
- return _('%(number)s years')%{'number': self.year}
+ s = _('%(number)s years')%{'number': self.year}
elif self.month or self.day > 13:
days = (self.month * 30) + self.day
if days > 28:
self.day, self.hour, self.minute, self.second)
def fixTimeOverflow(time):
- ''' Handle the overflow in the time portion (H, M, S) of "time":
+ """ Handle the overflow in the time portion (H, M, S) of "time":
(sign, y,m,d,H,M,S)
Overflow and underflow will at most affect the _days_ portion of
the date. We do not overflow days to months as we don't know _how_
to, generally.
- '''
+ """
# XXX we could conceivably use this function for handling regular dates
# XXX too - we just need to interrogate the month/year for the day
# XXX overflow...